3.1.78 \(\int \frac {1}{(a+a \sec (e+f x))^{3/2} (c-c \sec (e+f x))^3} \, dx\) [78]

3.1.78.1 Optimal result
3.1.78.2 Mathematica [C] (verified)
3.1.78.3 Rubi [A] (verified)
3.1.78.4 Maple [A] (verified)
3.1.78.5 Fricas [A] (verification not implemented)
3.1.78.6 Sympy [F]
3.1.78.7 Maxima [F]
3.1.78.8 Giac [F(-2)]
3.1.78.9 Mupad [F(-1)]

3.1.78.1 Optimal result

Integrand size = 28, antiderivative size = 249 \[ \int \frac {1}{(a+a \sec (e+f x))^{3/2} (c-c \sec (e+f x))^3} \, dx=\frac {2 \arctan \left (\frac {\sqrt {a} \tan (e+f x)}{\sqrt {a+a \sec (e+f x)}}\right )}{a^{3/2} c^3 f}-\frac {11 \arctan \left (\frac {\sqrt {a} \tan (e+f x)}{\sqrt {2} \sqrt {a+a \sec (e+f x)}}\right )}{16 \sqrt {2} a^{3/2} c^3 f}+\frac {21 \cot (e+f x) \sqrt {a+a \sec (e+f x)}}{16 a^2 c^3 f}-\frac {5 \cot ^3(e+f x) (a+a \sec (e+f x))^{3/2}}{24 a^3 c^3 f}-\frac {3 \cot ^5(e+f x) (a+a \sec (e+f x))^{5/2}}{20 a^4 c^3 f}+\frac {\cos (e+f x) \cot ^5(e+f x) \sec ^2\left (\frac {1}{2} (e+f x)\right ) (a+a \sec (e+f x))^{5/2}}{4 a^4 c^3 f} \]

output
2*arctan(a^(1/2)*tan(f*x+e)/(a+a*sec(f*x+e))^(1/2))/a^(3/2)/c^3/f-5/24*cot 
(f*x+e)^3*(a+a*sec(f*x+e))^(3/2)/a^3/c^3/f-3/20*cot(f*x+e)^5*(a+a*sec(f*x+ 
e))^(5/2)/a^4/c^3/f+1/4*cos(f*x+e)*cot(f*x+e)^5*sec(1/2*f*x+1/2*e)^2*(a+a* 
sec(f*x+e))^(5/2)/a^4/c^3/f-11/32*arctan(1/2*a^(1/2)*tan(f*x+e)*2^(1/2)/(a 
+a*sec(f*x+e))^(1/2))/a^(3/2)/c^3/f*2^(1/2)+21/16*cot(f*x+e)*(a+a*sec(f*x+ 
e))^(1/2)/a^2/c^3/f
 
3.1.78.2 Mathematica [C] (verified)

Result contains higher order function than in optimal. Order 5 vs. order 3 in optimal.

Time = 0.60 (sec) , antiderivative size = 102, normalized size of antiderivative = 0.41 \[ \int \frac {1}{(a+a \sec (e+f x))^{3/2} (c-c \sec (e+f x))^3} \, dx=-\frac {\left (-10+11 \operatorname {Hypergeometric2F1}\left (-\frac {5}{2},1,-\frac {3}{2},\frac {1}{2} (1-\sec (e+f x))\right ) (1+\sec (e+f x))-8 \operatorname {Hypergeometric2F1}\left (-\frac {5}{2},1,-\frac {3}{2},1-\sec (e+f x)\right ) (1+\sec (e+f x))\right ) \tan (e+f x)}{20 c^3 f (-1+\sec (e+f x))^3 (a (1+\sec (e+f x)))^{3/2}} \]

input
Integrate[1/((a + a*Sec[e + f*x])^(3/2)*(c - c*Sec[e + f*x])^3),x]
 
output
-1/20*((-10 + 11*Hypergeometric2F1[-5/2, 1, -3/2, (1 - Sec[e + f*x])/2]*(1 
 + Sec[e + f*x]) - 8*Hypergeometric2F1[-5/2, 1, -3/2, 1 - Sec[e + f*x]]*(1 
 + Sec[e + f*x]))*Tan[e + f*x])/(c^3*f*(-1 + Sec[e + f*x])^3*(a*(1 + Sec[e 
 + f*x]))^(3/2))
 
3.1.78.3 Rubi [A] (verified)

Time = 0.54 (sec) , antiderivative size = 241, normalized size of antiderivative = 0.97, number of steps used = 16, number of rules used = 15, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.536, Rules used = {3042, 4392, 3042, 4375, 374, 25, 27, 445, 27, 445, 27, 445, 27, 397, 216}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \frac {1}{(a \sec (e+f x)+a)^{3/2} (c-c \sec (e+f x))^3} \, dx\)

\(\Big \downarrow \) 3042

\(\displaystyle \int \frac {1}{\left (a \csc \left (e+f x+\frac {\pi }{2}\right )+a\right )^{3/2} \left (c-c \csc \left (e+f x+\frac {\pi }{2}\right )\right )^3}dx\)

\(\Big \downarrow \) 4392

\(\displaystyle -\frac {\int \cot ^6(e+f x) (\sec (e+f x) a+a)^{3/2}dx}{a^3 c^3}\)

\(\Big \downarrow \) 3042

\(\displaystyle -\frac {\int \frac {\left (\csc \left (e+f x+\frac {\pi }{2}\right ) a+a\right )^{3/2}}{\cot \left (e+f x+\frac {\pi }{2}\right )^6}dx}{a^3 c^3}\)

\(\Big \downarrow \) 4375

\(\displaystyle \frac {2 \int \frac {\cot ^6(e+f x) (\sec (e+f x) a+a)^3}{\left (\frac {a \tan ^2(e+f x)}{\sec (e+f x) a+a}+1\right ) \left (\frac {a \tan ^2(e+f x)}{\sec (e+f x) a+a}+2\right )^2}d\left (-\frac {\tan (e+f x)}{\sqrt {\sec (e+f x) a+a}}\right )}{a^4 c^3 f}\)

\(\Big \downarrow \) 374

\(\displaystyle \frac {2 \left (\frac {\int -\frac {a \cot ^6(e+f x) (\sec (e+f x) a+a)^3 \left (\frac {7 a \tan ^2(e+f x)}{\sec (e+f x) a+a}+3\right )}{\left (\frac {a \tan ^2(e+f x)}{\sec (e+f x) a+a}+1\right ) \left (\frac {a \tan ^2(e+f x)}{\sec (e+f x) a+a}+2\right )}d\left (-\frac {\tan (e+f x)}{\sqrt {\sec (e+f x) a+a}}\right )}{4 a}+\frac {\cot ^5(e+f x) (a \sec (e+f x)+a)^{5/2}}{4 \left (\frac {a \tan ^2(e+f x)}{a \sec (e+f x)+a}+2\right )}\right )}{a^4 c^3 f}\)

\(\Big \downarrow \) 25

\(\displaystyle \frac {2 \left (\frac {\cot ^5(e+f x) (a \sec (e+f x)+a)^{5/2}}{4 \left (\frac {a \tan ^2(e+f x)}{a \sec (e+f x)+a}+2\right )}-\frac {\int \frac {a \cot ^6(e+f x) (\sec (e+f x) a+a)^3 \left (\frac {7 a \tan ^2(e+f x)}{\sec (e+f x) a+a}+3\right )}{\left (\frac {a \tan ^2(e+f x)}{\sec (e+f x) a+a}+1\right ) \left (\frac {a \tan ^2(e+f x)}{\sec (e+f x) a+a}+2\right )}d\left (-\frac {\tan (e+f x)}{\sqrt {\sec (e+f x) a+a}}\right )}{4 a}\right )}{a^4 c^3 f}\)

\(\Big \downarrow \) 27

\(\displaystyle \frac {2 \left (\frac {\cot ^5(e+f x) (a \sec (e+f x)+a)^{5/2}}{4 \left (\frac {a \tan ^2(e+f x)}{a \sec (e+f x)+a}+2\right )}-\frac {1}{4} \int \frac {\cot ^6(e+f x) (\sec (e+f x) a+a)^3 \left (\frac {7 a \tan ^2(e+f x)}{\sec (e+f x) a+a}+3\right )}{\left (\frac {a \tan ^2(e+f x)}{\sec (e+f x) a+a}+1\right ) \left (\frac {a \tan ^2(e+f x)}{\sec (e+f x) a+a}+2\right )}d\left (-\frac {\tan (e+f x)}{\sqrt {\sec (e+f x) a+a}}\right )\right )}{a^4 c^3 f}\)

\(\Big \downarrow \) 445

\(\displaystyle \frac {2 \left (\frac {1}{4} \left (\frac {1}{10} \int -\frac {5 a \cot ^4(e+f x) (\sec (e+f x) a+a)^2 \left (5-\frac {3 a \tan ^2(e+f x)}{\sec (e+f x) a+a}\right )}{\left (\frac {a \tan ^2(e+f x)}{\sec (e+f x) a+a}+1\right ) \left (\frac {a \tan ^2(e+f x)}{\sec (e+f x) a+a}+2\right )}d\left (-\frac {\tan (e+f x)}{\sqrt {\sec (e+f x) a+a}}\right )-\frac {3}{10} \cot ^5(e+f x) (a \sec (e+f x)+a)^{5/2}\right )+\frac {\cot ^5(e+f x) (a \sec (e+f x)+a)^{5/2}}{4 \left (\frac {a \tan ^2(e+f x)}{a \sec (e+f x)+a}+2\right )}\right )}{a^4 c^3 f}\)

\(\Big \downarrow \) 27

\(\displaystyle \frac {2 \left (\frac {1}{4} \left (-\frac {1}{2} a \int \frac {\cot ^4(e+f x) (\sec (e+f x) a+a)^2 \left (5-\frac {3 a \tan ^2(e+f x)}{\sec (e+f x) a+a}\right )}{\left (\frac {a \tan ^2(e+f x)}{\sec (e+f x) a+a}+1\right ) \left (\frac {a \tan ^2(e+f x)}{\sec (e+f x) a+a}+2\right )}d\left (-\frac {\tan (e+f x)}{\sqrt {\sec (e+f x) a+a}}\right )-\frac {3}{10} \cot ^5(e+f x) (a \sec (e+f x)+a)^{5/2}\right )+\frac {\cot ^5(e+f x) (a \sec (e+f x)+a)^{5/2}}{4 \left (\frac {a \tan ^2(e+f x)}{a \sec (e+f x)+a}+2\right )}\right )}{a^4 c^3 f}\)

\(\Big \downarrow \) 445

\(\displaystyle \frac {2 \left (\frac {1}{4} \left (-\frac {1}{2} a \left (\frac {5}{6} \cot ^3(e+f x) (a \sec (e+f x)+a)^{3/2}-\frac {1}{6} \int \frac {3 a \cot ^2(e+f x) (\sec (e+f x) a+a) \left (\frac {5 a \tan ^2(e+f x)}{\sec (e+f x) a+a}+21\right )}{\left (\frac {a \tan ^2(e+f x)}{\sec (e+f x) a+a}+1\right ) \left (\frac {a \tan ^2(e+f x)}{\sec (e+f x) a+a}+2\right )}d\left (-\frac {\tan (e+f x)}{\sqrt {\sec (e+f x) a+a}}\right )\right )-\frac {3}{10} \cot ^5(e+f x) (a \sec (e+f x)+a)^{5/2}\right )+\frac {\cot ^5(e+f x) (a \sec (e+f x)+a)^{5/2}}{4 \left (\frac {a \tan ^2(e+f x)}{a \sec (e+f x)+a}+2\right )}\right )}{a^4 c^3 f}\)

\(\Big \downarrow \) 27

\(\displaystyle \frac {2 \left (\frac {1}{4} \left (-\frac {1}{2} a \left (\frac {5}{6} \cot ^3(e+f x) (a \sec (e+f x)+a)^{3/2}-\frac {1}{2} a \int \frac {\cot ^2(e+f x) (\sec (e+f x) a+a) \left (\frac {5 a \tan ^2(e+f x)}{\sec (e+f x) a+a}+21\right )}{\left (\frac {a \tan ^2(e+f x)}{\sec (e+f x) a+a}+1\right ) \left (\frac {a \tan ^2(e+f x)}{\sec (e+f x) a+a}+2\right )}d\left (-\frac {\tan (e+f x)}{\sqrt {\sec (e+f x) a+a}}\right )\right )-\frac {3}{10} \cot ^5(e+f x) (a \sec (e+f x)+a)^{5/2}\right )+\frac {\cot ^5(e+f x) (a \sec (e+f x)+a)^{5/2}}{4 \left (\frac {a \tan ^2(e+f x)}{a \sec (e+f x)+a}+2\right )}\right )}{a^4 c^3 f}\)

\(\Big \downarrow \) 445

\(\displaystyle \frac {2 \left (\frac {1}{4} \left (-\frac {1}{2} a \left (\frac {5}{6} \cot ^3(e+f x) (a \sec (e+f x)+a)^{3/2}-\frac {1}{2} a \left (\frac {21}{2} \cot (e+f x) \sqrt {a \sec (e+f x)+a}-\frac {1}{2} \int \frac {a \left (\frac {21 a \tan ^2(e+f x)}{\sec (e+f x) a+a}+53\right )}{\left (\frac {a \tan ^2(e+f x)}{\sec (e+f x) a+a}+1\right ) \left (\frac {a \tan ^2(e+f x)}{\sec (e+f x) a+a}+2\right )}d\left (-\frac {\tan (e+f x)}{\sqrt {\sec (e+f x) a+a}}\right )\right )\right )-\frac {3}{10} \cot ^5(e+f x) (a \sec (e+f x)+a)^{5/2}\right )+\frac {\cot ^5(e+f x) (a \sec (e+f x)+a)^{5/2}}{4 \left (\frac {a \tan ^2(e+f x)}{a \sec (e+f x)+a}+2\right )}\right )}{a^4 c^3 f}\)

\(\Big \downarrow \) 27

\(\displaystyle \frac {2 \left (\frac {1}{4} \left (-\frac {1}{2} a \left (\frac {5}{6} \cot ^3(e+f x) (a \sec (e+f x)+a)^{3/2}-\frac {1}{2} a \left (\frac {21}{2} \cot (e+f x) \sqrt {a \sec (e+f x)+a}-\frac {1}{2} a \int \frac {\frac {21 a \tan ^2(e+f x)}{\sec (e+f x) a+a}+53}{\left (\frac {a \tan ^2(e+f x)}{\sec (e+f x) a+a}+1\right ) \left (\frac {a \tan ^2(e+f x)}{\sec (e+f x) a+a}+2\right )}d\left (-\frac {\tan (e+f x)}{\sqrt {\sec (e+f x) a+a}}\right )\right )\right )-\frac {3}{10} \cot ^5(e+f x) (a \sec (e+f x)+a)^{5/2}\right )+\frac {\cot ^5(e+f x) (a \sec (e+f x)+a)^{5/2}}{4 \left (\frac {a \tan ^2(e+f x)}{a \sec (e+f x)+a}+2\right )}\right )}{a^4 c^3 f}\)

\(\Big \downarrow \) 397

\(\displaystyle \frac {2 \left (\frac {1}{4} \left (-\frac {1}{2} a \left (\frac {5}{6} \cot ^3(e+f x) (a \sec (e+f x)+a)^{3/2}-\frac {1}{2} a \left (\frac {21}{2} \cot (e+f x) \sqrt {a \sec (e+f x)+a}-\frac {1}{2} a \left (32 \int \frac {1}{\frac {a \tan ^2(e+f x)}{\sec (e+f x) a+a}+1}d\left (-\frac {\tan (e+f x)}{\sqrt {\sec (e+f x) a+a}}\right )-11 \int \frac {1}{\frac {a \tan ^2(e+f x)}{\sec (e+f x) a+a}+2}d\left (-\frac {\tan (e+f x)}{\sqrt {\sec (e+f x) a+a}}\right )\right )\right )\right )-\frac {3}{10} \cot ^5(e+f x) (a \sec (e+f x)+a)^{5/2}\right )+\frac {\cot ^5(e+f x) (a \sec (e+f x)+a)^{5/2}}{4 \left (\frac {a \tan ^2(e+f x)}{a \sec (e+f x)+a}+2\right )}\right )}{a^4 c^3 f}\)

\(\Big \downarrow \) 216

\(\displaystyle \frac {2 \left (\frac {1}{4} \left (-\frac {1}{2} a \left (\frac {5}{6} \cot ^3(e+f x) (a \sec (e+f x)+a)^{3/2}-\frac {1}{2} a \left (\frac {21}{2} \cot (e+f x) \sqrt {a \sec (e+f x)+a}-\frac {1}{2} a \left (\frac {11 \arctan \left (\frac {\sqrt {a} \tan (e+f x)}{\sqrt {2} \sqrt {a \sec (e+f x)+a}}\right )}{\sqrt {2} \sqrt {a}}-\frac {32 \arctan \left (\frac {\sqrt {a} \tan (e+f x)}{\sqrt {a \sec (e+f x)+a}}\right )}{\sqrt {a}}\right )\right )\right )-\frac {3}{10} \cot ^5(e+f x) (a \sec (e+f x)+a)^{5/2}\right )+\frac {\cot ^5(e+f x) (a \sec (e+f x)+a)^{5/2}}{4 \left (\frac {a \tan ^2(e+f x)}{a \sec (e+f x)+a}+2\right )}\right )}{a^4 c^3 f}\)

input
Int[1/((a + a*Sec[e + f*x])^(3/2)*(c - c*Sec[e + f*x])^3),x]
 
output
(2*(((-3*Cot[e + f*x]^5*(a + a*Sec[e + f*x])^(5/2))/10 - (a*((5*Cot[e + f* 
x]^3*(a + a*Sec[e + f*x])^(3/2))/6 - (a*(-1/2*(a*((-32*ArcTan[(Sqrt[a]*Tan 
[e + f*x])/Sqrt[a + a*Sec[e + f*x]]])/Sqrt[a] + (11*ArcTan[(Sqrt[a]*Tan[e 
+ f*x])/(Sqrt[2]*Sqrt[a + a*Sec[e + f*x]])])/(Sqrt[2]*Sqrt[a]))) + (21*Cot 
[e + f*x]*Sqrt[a + a*Sec[e + f*x]])/2))/2))/2)/4 + (Cot[e + f*x]^5*(a + a* 
Sec[e + f*x])^(5/2))/(4*(2 + (a*Tan[e + f*x]^2)/(a + a*Sec[e + f*x])))))/( 
a^4*c^3*f)
 

3.1.78.3.1 Defintions of rubi rules used

rule 25
Int[-(Fx_), x_Symbol] :> Simp[Identity[-1]   Int[Fx, x], x]
 

rule 27
Int[(a_)*(Fx_), x_Symbol] :> Simp[a   Int[Fx, x], x] /; FreeQ[a, x] &&  !Ma 
tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
 

rule 216
Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(1/(Rt[a, 2]*Rt[b, 2]))*A 
rcTan[Rt[b, 2]*(x/Rt[a, 2])], x] /; FreeQ[{a, b}, x] && PosQ[a/b] && (GtQ[a 
, 0] || GtQ[b, 0])
 

rule 374
Int[((e_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^2)^(p_)*((c_) + (d_.)*(x_)^2)^(q_ 
), x_Symbol] :> Simp[(-b)*(e*x)^(m + 1)*(a + b*x^2)^(p + 1)*((c + d*x^2)^(q 
 + 1)/(a*e*2*(b*c - a*d)*(p + 1))), x] + Simp[1/(a*2*(b*c - a*d)*(p + 1)) 
 Int[(e*x)^m*(a + b*x^2)^(p + 1)*(c + d*x^2)^q*Simp[b*c*(m + 1) + 2*(b*c - 
a*d)*(p + 1) + d*b*(m + 2*(p + q + 2) + 1)*x^2, x], x], x] /; FreeQ[{a, b, 
c, d, e, m, q}, x] && NeQ[b*c - a*d, 0] && LtQ[p, -1] && IntBinomialQ[a, b, 
 c, d, e, m, 2, p, q, x]
 

rule 397
Int[((e_) + (f_.)*(x_)^2)/(((a_) + (b_.)*(x_)^2)*((c_) + (d_.)*(x_)^2)), x_ 
Symbol] :> Simp[(b*e - a*f)/(b*c - a*d)   Int[1/(a + b*x^2), x], x] - Simp[ 
(d*e - c*f)/(b*c - a*d)   Int[1/(c + d*x^2), x], x] /; FreeQ[{a, b, c, d, e 
, f}, x]
 

rule 445
Int[((g_.)*(x_))^(m_)*((a_) + (b_.)*(x_)^2)^(p_.)*((c_) + (d_.)*(x_)^2)^(q_ 
.)*((e_) + (f_.)*(x_)^2), x_Symbol] :> Simp[e*(g*x)^(m + 1)*(a + b*x^2)^(p 
+ 1)*((c + d*x^2)^(q + 1)/(a*c*g*(m + 1))), x] + Simp[1/(a*c*g^2*(m + 1)) 
 Int[(g*x)^(m + 2)*(a + b*x^2)^p*(c + d*x^2)^q*Simp[a*f*c*(m + 1) - e*(b*c 
+ a*d)*(m + 2 + 1) - e*2*(b*c*p + a*d*q) - b*e*d*(m + 2*(p + q + 2) + 1)*x^ 
2, x], x], x] /; FreeQ[{a, b, c, d, e, f, g, p, q}, x] && LtQ[m, -1]
 

rule 3042
Int[u_, x_Symbol] :> Int[DeactivateTrig[u, x], x] /; FunctionOfTrigOfLinear 
Q[u, x]
 

rule 4375
Int[cot[(c_.) + (d_.)*(x_)]^(m_.)*(csc[(c_.) + (d_.)*(x_)]*(b_.) + (a_))^(n 
_.), x_Symbol] :> Simp[-2*(a^(m/2 + n + 1/2)/d)   Subst[Int[x^m*((2 + a*x^2 
)^(m/2 + n - 1/2)/(1 + a*x^2)), x], x, Cot[c + d*x]/Sqrt[a + b*Csc[c + d*x] 
]], x] /; FreeQ[{a, b, c, d}, x] && EqQ[a^2 - b^2, 0] && IntegerQ[m/2] && I 
ntegerQ[n - 1/2]
 

rule 4392
Int[(csc[(e_.) + (f_.)*(x_)]*(b_.) + (a_))^(m_.)*(csc[(e_.) + (f_.)*(x_)]*( 
d_.) + (c_))^(n_.), x_Symbol] :> Simp[((-a)*c)^m   Int[Cot[e + f*x]^(2*m)*( 
c + d*Csc[e + f*x])^(n - m), x], x] /; FreeQ[{a, b, c, d, e, f, n}, x] && E 
qQ[b*c + a*d, 0] && EqQ[a^2 - b^2, 0] && IntegerQ[m] && RationalQ[n] &&  !( 
IntegerQ[n] && GtQ[m - n, 0])
 
3.1.78.4 Maple [A] (verified)

Time = 2.75 (sec) , antiderivative size = 232, normalized size of antiderivative = 0.93

method result size
default \(-\frac {\left (165 \sin \left (f x +e \right )^{5} \sqrt {2}\, \sqrt {-\frac {\cos \left (f x +e \right )}{\cos \left (f x +e \right )+1}}\, \ln \left (\csc \left (f x +e \right )-\cot \left (f x +e \right )+\sqrt {\cot \left (f x +e \right )^{2}-2 \csc \left (f x +e \right ) \cot \left (f x +e \right )+\csc \left (f x +e \right )^{2}-1}\right )-960 \sin \left (f x +e \right )^{5} \sqrt {-\frac {\cos \left (f x +e \right )}{\cos \left (f x +e \right )+1}}\, \operatorname {arctanh}\left (\frac {\sin \left (f x +e \right )}{\left (\cos \left (f x +e \right )+1\right ) \sqrt {-\frac {\cos \left (f x +e \right )}{\cos \left (f x +e \right )+1}}}\right )-898 \cos \left (f x +e \right )^{5}-196 \cos \left (f x +e \right )^{4}+1432 \cos \left (f x +e \right )^{3}+100 \cos \left (f x +e \right )^{2}-630 \cos \left (f x +e \right )\right ) \sqrt {a \left (\sec \left (f x +e \right )+1\right )}\, \csc \left (f x +e \right )^{5}}{480 c^{3} f \,a^{2}}\) \(232\)

input
int(1/(a+a*sec(f*x+e))^(3/2)/(c-c*sec(f*x+e))^3,x,method=_RETURNVERBOSE)
 
output
-1/480/c^3/f/a^2*(165*sin(f*x+e)^5*2^(1/2)*(-cos(f*x+e)/(cos(f*x+e)+1))^(1 
/2)*ln(csc(f*x+e)-cot(f*x+e)+(cot(f*x+e)^2-2*csc(f*x+e)*cot(f*x+e)+csc(f*x 
+e)^2-1)^(1/2))-960*sin(f*x+e)^5*(-cos(f*x+e)/(cos(f*x+e)+1))^(1/2)*arctan 
h(sin(f*x+e)/(cos(f*x+e)+1)/(-cos(f*x+e)/(cos(f*x+e)+1))^(1/2))-898*cos(f* 
x+e)^5-196*cos(f*x+e)^4+1432*cos(f*x+e)^3+100*cos(f*x+e)^2-630*cos(f*x+e)) 
*(a*(sec(f*x+e)+1))^(1/2)*csc(f*x+e)^5
 
3.1.78.5 Fricas [A] (verification not implemented)

Time = 0.40 (sec) , antiderivative size = 714, normalized size of antiderivative = 2.87 \[ \int \frac {1}{(a+a \sec (e+f x))^{3/2} (c-c \sec (e+f x))^3} \, dx=\left [-\frac {165 \, \sqrt {2} {\left (\cos \left (f x + e\right )^{3} - \cos \left (f x + e\right )^{2} - \cos \left (f x + e\right ) + 1\right )} \sqrt {-a} \log \left (-\frac {2 \, \sqrt {2} \sqrt {-a} \sqrt {\frac {a \cos \left (f x + e\right ) + a}{\cos \left (f x + e\right )}} \cos \left (f x + e\right ) \sin \left (f x + e\right ) - 3 \, a \cos \left (f x + e\right )^{2} - 2 \, a \cos \left (f x + e\right ) + a}{\cos \left (f x + e\right )^{2} + 2 \, \cos \left (f x + e\right ) + 1}\right ) \sin \left (f x + e\right ) + 480 \, {\left (\cos \left (f x + e\right )^{3} - \cos \left (f x + e\right )^{2} - \cos \left (f x + e\right ) + 1\right )} \sqrt {-a} \log \left (-\frac {8 \, a \cos \left (f x + e\right )^{3} + 4 \, {\left (2 \, \cos \left (f x + e\right )^{2} - \cos \left (f x + e\right )\right )} \sqrt {-a} \sqrt {\frac {a \cos \left (f x + e\right ) + a}{\cos \left (f x + e\right )}} \sin \left (f x + e\right ) - 7 \, a \cos \left (f x + e\right ) + a}{\cos \left (f x + e\right ) + 1}\right ) \sin \left (f x + e\right ) - 4 \, {\left (449 \, \cos \left (f x + e\right )^{4} - 351 \, \cos \left (f x + e\right )^{3} - 365 \, \cos \left (f x + e\right )^{2} + 315 \, \cos \left (f x + e\right )\right )} \sqrt {\frac {a \cos \left (f x + e\right ) + a}{\cos \left (f x + e\right )}}}{960 \, {\left (a^{2} c^{3} f \cos \left (f x + e\right )^{3} - a^{2} c^{3} f \cos \left (f x + e\right )^{2} - a^{2} c^{3} f \cos \left (f x + e\right ) + a^{2} c^{3} f\right )} \sin \left (f x + e\right )}, \frac {165 \, \sqrt {2} {\left (\cos \left (f x + e\right )^{3} - \cos \left (f x + e\right )^{2} - \cos \left (f x + e\right ) + 1\right )} \sqrt {a} \arctan \left (\frac {\sqrt {2} \sqrt {\frac {a \cos \left (f x + e\right ) + a}{\cos \left (f x + e\right )}} \cos \left (f x + e\right )}{\sqrt {a} \sin \left (f x + e\right )}\right ) \sin \left (f x + e\right ) + 480 \, {\left (\cos \left (f x + e\right )^{3} - \cos \left (f x + e\right )^{2} - \cos \left (f x + e\right ) + 1\right )} \sqrt {a} \arctan \left (\frac {2 \, \sqrt {a} \sqrt {\frac {a \cos \left (f x + e\right ) + a}{\cos \left (f x + e\right )}} \cos \left (f x + e\right ) \sin \left (f x + e\right )}{2 \, a \cos \left (f x + e\right )^{2} + a \cos \left (f x + e\right ) - a}\right ) \sin \left (f x + e\right ) + 2 \, {\left (449 \, \cos \left (f x + e\right )^{4} - 351 \, \cos \left (f x + e\right )^{3} - 365 \, \cos \left (f x + e\right )^{2} + 315 \, \cos \left (f x + e\right )\right )} \sqrt {\frac {a \cos \left (f x + e\right ) + a}{\cos \left (f x + e\right )}}}{480 \, {\left (a^{2} c^{3} f \cos \left (f x + e\right )^{3} - a^{2} c^{3} f \cos \left (f x + e\right )^{2} - a^{2} c^{3} f \cos \left (f x + e\right ) + a^{2} c^{3} f\right )} \sin \left (f x + e\right )}\right ] \]

input
integrate(1/(a+a*sec(f*x+e))^(3/2)/(c-c*sec(f*x+e))^3,x, algorithm="fricas 
")
 
output
[-1/960*(165*sqrt(2)*(cos(f*x + e)^3 - cos(f*x + e)^2 - cos(f*x + e) + 1)* 
sqrt(-a)*log(-(2*sqrt(2)*sqrt(-a)*sqrt((a*cos(f*x + e) + a)/cos(f*x + e))* 
cos(f*x + e)*sin(f*x + e) - 3*a*cos(f*x + e)^2 - 2*a*cos(f*x + e) + a)/(co 
s(f*x + e)^2 + 2*cos(f*x + e) + 1))*sin(f*x + e) + 480*(cos(f*x + e)^3 - c 
os(f*x + e)^2 - cos(f*x + e) + 1)*sqrt(-a)*log(-(8*a*cos(f*x + e)^3 + 4*(2 
*cos(f*x + e)^2 - cos(f*x + e))*sqrt(-a)*sqrt((a*cos(f*x + e) + a)/cos(f*x 
 + e))*sin(f*x + e) - 7*a*cos(f*x + e) + a)/(cos(f*x + e) + 1))*sin(f*x + 
e) - 4*(449*cos(f*x + e)^4 - 351*cos(f*x + e)^3 - 365*cos(f*x + e)^2 + 315 
*cos(f*x + e))*sqrt((a*cos(f*x + e) + a)/cos(f*x + e)))/((a^2*c^3*f*cos(f* 
x + e)^3 - a^2*c^3*f*cos(f*x + e)^2 - a^2*c^3*f*cos(f*x + e) + a^2*c^3*f)* 
sin(f*x + e)), 1/480*(165*sqrt(2)*(cos(f*x + e)^3 - cos(f*x + e)^2 - cos(f 
*x + e) + 1)*sqrt(a)*arctan(sqrt(2)*sqrt((a*cos(f*x + e) + a)/cos(f*x + e) 
)*cos(f*x + e)/(sqrt(a)*sin(f*x + e)))*sin(f*x + e) + 480*(cos(f*x + e)^3 
- cos(f*x + e)^2 - cos(f*x + e) + 1)*sqrt(a)*arctan(2*sqrt(a)*sqrt((a*cos( 
f*x + e) + a)/cos(f*x + e))*cos(f*x + e)*sin(f*x + e)/(2*a*cos(f*x + e)^2 
+ a*cos(f*x + e) - a))*sin(f*x + e) + 2*(449*cos(f*x + e)^4 - 351*cos(f*x 
+ e)^3 - 365*cos(f*x + e)^2 + 315*cos(f*x + e))*sqrt((a*cos(f*x + e) + a)/ 
cos(f*x + e)))/((a^2*c^3*f*cos(f*x + e)^3 - a^2*c^3*f*cos(f*x + e)^2 - a^2 
*c^3*f*cos(f*x + e) + a^2*c^3*f)*sin(f*x + e))]
 
3.1.78.6 Sympy [F]

\[ \int \frac {1}{(a+a \sec (e+f x))^{3/2} (c-c \sec (e+f x))^3} \, dx=- \frac {\int \frac {1}{a \sqrt {a \sec {\left (e + f x \right )} + a} \sec ^{4}{\left (e + f x \right )} - 2 a \sqrt {a \sec {\left (e + f x \right )} + a} \sec ^{3}{\left (e + f x \right )} + 2 a \sqrt {a \sec {\left (e + f x \right )} + a} \sec {\left (e + f x \right )} - a \sqrt {a \sec {\left (e + f x \right )} + a}}\, dx}{c^{3}} \]

input
integrate(1/(a+a*sec(f*x+e))**(3/2)/(c-c*sec(f*x+e))**3,x)
 
output
-Integral(1/(a*sqrt(a*sec(e + f*x) + a)*sec(e + f*x)**4 - 2*a*sqrt(a*sec(e 
 + f*x) + a)*sec(e + f*x)**3 + 2*a*sqrt(a*sec(e + f*x) + a)*sec(e + f*x) - 
 a*sqrt(a*sec(e + f*x) + a)), x)/c**3
 
3.1.78.7 Maxima [F]

\[ \int \frac {1}{(a+a \sec (e+f x))^{3/2} (c-c \sec (e+f x))^3} \, dx=\int { -\frac {1}{{\left (a \sec \left (f x + e\right ) + a\right )}^{\frac {3}{2}} {\left (c \sec \left (f x + e\right ) - c\right )}^{3}} \,d x } \]

input
integrate(1/(a+a*sec(f*x+e))^(3/2)/(c-c*sec(f*x+e))^3,x, algorithm="maxima 
")
 
output
-integrate(1/((a*sec(f*x + e) + a)^(3/2)*(c*sec(f*x + e) - c)^3), x)
 
3.1.78.8 Giac [F(-2)]

Exception generated. \[ \int \frac {1}{(a+a \sec (e+f x))^{3/2} (c-c \sec (e+f x))^3} \, dx=\text {Exception raised: TypeError} \]

input
integrate(1/(a+a*sec(f*x+e))^(3/2)/(c-c*sec(f*x+e))^3,x, algorithm="giac")
 
output
Exception raised: TypeError >> an error occurred running a Giac command:IN 
PUT:sage2:=int(sage0,sageVARx):;OUTPUT:index.cc index_m i_lex_is_greater E 
rror: Bad Argument Value
 
3.1.78.9 Mupad [F(-1)]

Timed out. \[ \int \frac {1}{(a+a \sec (e+f x))^{3/2} (c-c \sec (e+f x))^3} \, dx=\int \frac {1}{{\left (a+\frac {a}{\cos \left (e+f\,x\right )}\right )}^{3/2}\,{\left (c-\frac {c}{\cos \left (e+f\,x\right )}\right )}^3} \,d x \]

input
int(1/((a + a/cos(e + f*x))^(3/2)*(c - c/cos(e + f*x))^3),x)
 
output
int(1/((a + a/cos(e + f*x))^(3/2)*(c - c/cos(e + f*x))^3), x)